The CBSE Class 10 board exam rewards steady practice more than last-minute revision. The syllabus is well defined, the question patterns repeat, and students who solve a mix of problems from every chapter through the year walk into the exam calm and quick. Maths Daily Helper gives you unlimited fresh Class 10 questions, matched to the NCERT chapters, each with a full worked solution so you learn the method the board expects, not just the answer.
Chapters covered
- Real Numbers (Euclid's division lemma, HCF and LCM, irrational numbers)
- Polynomials (zeroes, relationship between zeroes and coefficients)
- Pair of Linear Equations in Two Variables
- Quadratic Equations
- Arithmetic Progressions
- Triangles (similarity, Pythagoras)
- Coordinate Geometry (distance and section formulae)
- Introduction to Trigonometry and its Applications
- Circles and Areas Related to Circles
- Surface Areas and Volumes
- Statistics and Probability
Try a few Class 10 problems
Work each one out first, then check your steps.
Find the roots of the equation x² − 5x + 6 = 0.
1. Factorise: look for two numbers that multiply to 6 and add to −5. Those are −2 and −3.
2. So x² − 5x + 6 = (x − 2)(x − 3) = 0.
3. Set each factor to zero: x − 2 = 0 or x − 3 = 0.
Answer: x = 2 or x = 3.
If sin θ = 3/5, find the value of cos θ, where θ is acute.
1. Use the identity sin²θ + cos²θ = 1.
2. cos²θ = 1 − (3/5)² = 1 − 9/25 = 16/25.
3. Since θ is acute, cos θ is positive: cos θ = √(16/25) = 4/5.
Answer: cos θ = 4/5.
Find the 15th term of the AP: 3, 7, 11, 15, …
1. First term a = 3, common difference d = 7 − 3 = 4.
2. The nth term is aₙ = a + (n − 1)d.
3. a₁₅ = 3 + (15 − 1)·4 = 3 + 56 = 59.
Answer: 59.
Find the HCF of 96 and 404 using the prime factorisation method.
1. 96 = 2⁵ × 3. 404 = 2² × 101.
2. The common prime factor is 2, taken to the lowest power present in both: 2².
3. HCF = 2² = 4.
Answer: 4.
If α and β are the zeroes of x² − 5x + 6, find α + β and αβ.
1. For ax² + bx + c, sum of zeroes = −b/a and product = c/a.
2. Here a = 1, b = −5, c = 6, so α + β = −(−5)/1 = 5.
3. αβ = 6/1 = 6.
Answer: α + β = 5, αβ = 6.
Find the distance between the points (2, 3) and (5, 7).
1. Distance formula: √[(x₂ − x₁)² + (y₂ − y₁)²].
2. = √[(5 − 2)² + (7 − 3)²] = √[3² + 4²] = √[9 + 16] = √25.
Answer: 5 units.
Find the volume of a sphere of radius 7 cm. (Use π = 22/7.)
1. Volume of a sphere = (4/3)πr³.
2. = (4/3) × (22/7) × 7³ = (4/3) × (22/7) × 343.
3. = (4/3) × 22 × 49 = (4 × 22 × 49)/3 = 4312/3 ≈ 1437.33.
Answer: 4312/3 cm³ ≈ 1437.33 cm³.
A bag contains 5 red and 3 blue balls. One ball is drawn at random. What is the probability it is red?
1. Total balls = 5 + 3 = 8.
2. Favourable outcomes (red) = 5.
3. Probability = 5/8.
Answer: 5/8.
Practise every chapter, unlimited
Choose Class 10 and any chapter. Get a fresh question each time, with hints and full solutions.
Open Maths Daily Helper →A simple daily routine for the board exam
Aim for ten to fifteen questions a day across two or three chapters, rotating so no topic goes cold. Do the ones you find hardest first, while you are fresh. Use hints before solutions so you build the habit of finding the next step yourself, which is exactly what the three-hour board paper tests. Closer to the exam, switch to generating full sample papers and time yourself, so pace and presentation become automatic.