ICSE Class 10 maths is known for its breadth and its strong emphasis on commercial mathematics, GST, banking, and shares and dividends, alongside the usual algebra, geometry and trigonometry. The board rewards clear, complete working, so practising with full solutions to model the expected method matters as much as getting the right answer. Maths Daily Helper generates unlimited fresh ICSE Class 10 questions matched to the syllabus, each with a step-by-step solution.
Topics covered
- Commercial mathematics: GST, banking (recurring deposits), shares and dividends.
- Algebra: linear inequations, quadratic equations, ratio and proportion, factor and remainder theorems, matrices, arithmetic and geometric progressions.
- Geometry: similarity, loci, circles, constructions.
- Mensuration: cylinder, cone, sphere.
- Trigonometry: identities, heights and distances.
- Statistics and probability.
Try a few ICSE Class 10 problems
Work each one out first, then check your steps.
An article costs ₹2,000 and attracts GST at 18%. Find the total amount paid.
1. GST = 18% of 2000 = 0.18 × 2000 = 360.
2. Total = cost + GST = 2000 + 360.
Answer: ₹2,360.
Find the annual dividend on 100 shares of face value ₹10 each, paying a dividend of 8%.
1. Total face value = 100 × 10 = ₹1,000.
2. Dividend = 8% of 1000 = 0.08 × 1000.
Answer: ₹80.
Solve x² − 3x − 10 = 0.
1. Find two numbers multiplying to −10 and adding to −3: −5 and 2.
2. Factorise: (x − 5)(x + 2) = 0.
3. So x = 5 or x = −2.
Answer: x = 5 or x = −2.
If A = [[1, 2], [3, 4]], find 2A.
1. Multiply every element by the scalar 2.
2. 2A = [[2, 4], [6, 8]].
Answer: [[2, 4], [6, 8]].
Prove that sin²θ + cos²θ = 1 holds for θ = 30° by substitution.
1. sin 30° = 1/2, so sin²30° = 1/4. cos 30° = √3/2, so cos²30° = 3/4.
2. Add: 1/4 + 3/4 = 4/4 = 1.
Verified: sin²30° + cos²30° = 1.
Two similar triangles have areas in the ratio 9 : 16. Find the ratio of their corresponding sides.
1. For similar triangles, the ratio of areas equals the square of the ratio of sides.
2. So (side ratio)² = 9/16, giving side ratio = √(9/16) = 3/4.
Answer: 3 : 4.
Find the curved surface area of a cylinder of radius 7 cm and height 10 cm. (Use π = 22/7.)
1. Curved surface area = 2πrh.
2. = 2 × (22/7) × 7 × 10 = 2 × 22 × 10.
Answer: 440 cm².
Find the 10th term of the AP: 5, 8, 11, 14, …
1. First term a = 5, common difference d = 3.
2. nth term aₙ = a + (n − 1)d = 5 + (10 − 1)(3) = 5 + 27.
Answer: 32.
Practise every topic, unlimited
Choose ICSE Class 10 and any topic. Get a fresh question each time, with hints and full solutions.
Open Maths Daily Helper →A daily routine for the ICSE board exam
The ICSE paper rewards full, well-presented working, so practise writing out every step, not just the final answer. Ten to fifteen questions a day across two or three topics keeps the wide syllabus fresh. Give the commercial mathematics topics regular attention since they carry reliable marks and reward careful arithmetic. Closer to the exam, generate full sample papers and time yourself so presentation and pace become automatic.